Question
Download Solution PDF25 मिमी व्यास और 250 मिमी लंबाई के पीतल की छड़ के यंग मापांक ज्ञात करें, जिसे 50 kN के तन्य भार के अधीनकृत किया जाता है, जब रॉड का विस्तार 0.3 मिमी के बराबर होता है ।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Elongation of a circular bar:
Extension of the rod under the axial pull,
\(\delta l = \frac{P.L}{(\frac{\pi}{4}).(d^2)E}\)
Where, P= load applied, L = length of the bar, E = Modulus of elasticity, d = diameter of the bar
Calculation:
Given,
L = 250 mm
δL = 0.3 mm, P = 50 kN, d = 25 mm
\(0.3 = \frac{50000 \times 250}{(\frac{\pi}{4}).(25^2)E}\)
⇒ E = 84882.64 MPa
⇒ E = 84.883 GPa or 84.883 GN/m2
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