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From a taxi stand, two cabs start at a speed of 54 km/hr at an interval of 29 minutes, both cabs travelling in the same direction. A man coming in the opposite direction towards the taxi stand meets the cabs at an interval of 12 minutes. Find the speed (in km/hr) of the man.

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RRB NTPC Graduate Level CBT-I Official Paper (Held On: 05 Jun, 2025 Shift 3)
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  1. 80.4
  2. 82.1
  3. 76.5
  4. 74.8

Answer (Detailed Solution Below)

Option 3 : 76.5
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Detailed Solution

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Given:

Speed of both cabs = 54 km/hr

Time gap between cab departures = 29 minutes

Man meets the cabs at an interval of 12 minutes

Formula used:

Distance between cabs = Relative speed (man & cab) × time between meetings

Calculations:

⇒ Distance between cabs = 54 × (29 ÷ 60) = 54 × 0.4833 = 26.1 km

⇒ Relative speed when man meets cab = Distance ÷ (12 ÷ 60) = 26.1 ÷ 0.2 = 130.5 km/hr

⇒ Man’s speed = Relative speed − Cab speed = 130.5 − 54 = 76.5 km/hr

∴ The speed of the man is 76.5 km/hr.

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Q1.From a taxi stand, two cabs start at a speed of 54 km/hr at an interval of 29 minutes, both cabs travelling in the same direction. A man coming in the opposite direction towards the taxi stand meets the cabs at an interval of 12 minutes. Find the speed (in km/hr) of the man.
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