For a given reaction A2(g) + 3B22(g) ⇋ 2AB3(g), ΔH = —ve

For this reaction, the favorable condition for decomposition of AB3 is: 

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DSSSB PGT Chemistry (Female) Official Paper (Held On: 06 Jul, 2018 Shift 1)
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  1. High temperature, low pressure 
  2. Low temperature, low pressure 
  3. High temperature, high pressure 
  4. Low temperature, high pressure  

Answer (Detailed Solution Below)

Option 1 : High temperature, low pressure 
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Detailed Solution

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CONCEPT:

Le Chatelier's Principle

  • Le Chatelier's Principle states that if a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium moves to counteract the change.
  • For a reaction involving gases, the effect of pressure and temperature can be analyzed as follows:
    • Pressure: Increasing pressure favors the side with fewer moles of gas, while decreasing pressure favors the side with more moles of gas.
    • Temperature: For an exothermic reaction (ΔH = —ve), increasing temperature shifts the equilibrium toward the reactants (decomposition), while decreasing temperature favors the products.

EXPLANATION:

  • The given reaction is:

    A2(g) + 3B2(g) ⇋ 2AB3(g), ΔH = —ve

  • To favor the decomposition of AB3 (i.e., shifting the equilibrium toward the reactants A2 and B2), we analyze the conditions:
    • Effect of Pressure: The forward reaction forms 2 moles of AB3 from 4 moles of reactants (1 mole of A2 and 3 moles of B2). Decreasing pressure will favor the backward reaction since it produces more moles of gas.
    • Effect of Temperature: The reaction is exothermic (ΔH = —ve). Increasing temperature will favor the backward (endothermic) reaction, leading to decomposition of AB3.

Therefore, the favorable condition for decomposition of AB3 is high temperature and low pressure.

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