Find the density (in kg/m3) of a piece of wood of dimensions 6 cm × 8 cm × 5 cm, and weight 1.92 N. (Use g = 10 m/s2)  

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RRB ALP Fitter 23 Jan 2019 Official Paper (Shift 2).
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  1. 300
  2. 3,000
  3. 800
  4. 8,000

Answer (Detailed Solution Below)

Option 3 : 800
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Concept:

Density:

  • Density is the measurement of how tightly a material is packed together.
  • It is defined as the mass per unit volume.

Mathematically, \(\rho =\frac{Mass}{Volume}\)

Calculation:

Given:

dimensions of wood = 6 cm × 8 cm × 5 cm, weight = 1.92 N, g = 10 m/s2

Weight = mass × gravity

⇒ 1.92 = mass × 10

\(mass=\frac{1.92}{10}=0.192~kg\)

∵ Density, ρ = \(\frac{Mass}{Volume}\)

⇒ ρ = \(\frac{0.192}{0.06~\times~0.08~\times~0.05}\)

⇒ ρ = 800 kg/m3

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