A truck initially at rest travels a distance of 70 m in 7 seconds and the motion continues in the same manner. If the body executes a uniformly accelerated motion, then acceleration (a) is (approx.)

Question

Question

Answer 1

CONCEPT:

The equations of motion are used to characterize the movement of the body and are given by

\(S = ut+ \frac{1}{2}a t^{2}\)

V = u + at

V² = U²+ 2as

Where S = Displacement, t = time a = acceleration, V = Final velocity, U = Initial velocity

CALCULATION:

Given S = 70 m, t = 7 sec u = 0m/s

The equation of motion connecting displacement, initial velocity, and time is given by

\(⇒ S = ut+ \frac{1}{2}a t^{2}\)

substituting the given values the above equation becomes

\(\Rightarrow 70 = 0\times 7+ \frac{1}{2}a \times 7^{2}\)

\(\Rightarrow a = \frac{70\times 2}{7\times 7} = \frac{20}{7} = 2.85m/s^{2}\)