A symmetrical biconvex lens of focal length 'f' is cut into four identical pieces along and perpendicular to its principal axis The focal length of each of four pieces is

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ALP CBT 2 Physics and Maths Previous Paper 4 (Held On: 22 Jan 2019 Shift 1)
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  1. 4f
  2. f / 4
  3. 2f
  4. f / 2

Answer (Detailed Solution Below)

Option 3 : 2f
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CONCEPT:

  • Lens: The transparent curved surface which is used to refract the light and make an image of any object placed in front of it is called a lens.
    • Convex lens: ​A lens having two spherical surfaces, bulging outwards is called a double convex lens (or simply convex lens).
      • It is thicker in the middle as compared to the edges.
    • Convex lenses converge light rays and hence, convex lenses are also called converging lenses.

EXPLANATION:

  • The lens maker’s formula is given by:

\(⇒ \frac{1}{f} = \left( {n - 1} \right)\left( {\frac{1}{{{R_1}}} - \frac{1}{{{R_2}}}} \right)\)

Where, f is the focal length (half the radius of curvature), n is the refractive index of the material used, R1 is the radius of curvature of sphere 1 and R2 is the radius of curvature of sphere 2

  • For equiconvex lens

\(⇒ \frac{1}{f} = \left( {n - 1} \right)\left( {\frac{1}{{{R}}} + \frac{1}{{{R}}}} \right)=(n-1)\frac{2}{R}\)      -------- (1)

  • If a biconvex lens is cut perpendicular to its principal axis, then it will become the plano-convex lens and then the focal length of the plano-convex lens is 

\(⇒ \frac{1}{f'} =(n-1)\frac{1}{R}\)      ------ (2)

From 1 and 2, we get

⇒ f' = 2f

  • The focal length of each of the four pieces is 2f. Therefore option 3 is correct.
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