Question
Download Solution PDFA single phase transmission line is transmitting 1,100 KW power at 11 kV and at unity power factor. If it has a total resistance of 5 Ω, what is the efficiency of the transmission line?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
Power transmitted (P0) = 1,100 kW
Voltage (V) = 11 kV = 11,000 V
Resistance (R) = 5 Ω
Power factor = 1 (Unity)
Current (I) = \(\frac{{1,100,000}}{{11,000}} = 100\;A\)
Total power loss in the transmission line,
Ploss = I2 R
⇒ Ploss = (100)2 × 5 = 50 KW
Input power (Pin) = P0 + Ploss
⇒ Pin = 1,100 kW + 50 kW = 1,150 kW
\(Efficiency\left( \eta \right) = \frac{{1,100}}{{1,150}} \times 100 = 95.65 \%\)Conclusion:
The efficiency of the transmission line is approximately 95.65%, which is closest to 99.54%.
Last updated on Jun 16, 2025
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