A nuclear reactor produces 3.2×10¹⁰ J of energy per second. How many fissions occur per second if each fission releases 200 MeV?

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RRB JE EE 22 Apr 2025 Shift 1 CBT 2 Official Paper

Answer 1

Given, Energy per fission = 200 MeV

Total energy per second = 3.204 × 10-11 Joules per fission

1 eV = $1.602 \times 1 0 -19$ joules

200 MeV = 200 × 10⁶ × $1.602 \times 1 0 -19$ = 3.204 × 10^-11 J per fission

Fissions per second = ${Total \space  energy\space per\space second \over Energy \space per \space fission}$

Fissions per second = ${3.2\times 10^{10} \over 3.204\times 10^{-11}}$

Fissions per second = 1021