Question
Download Solution PDFA hydraulic press has a ram of cross-section area 30 × 30 cm and a plunger of cross-section area 4 × 4 cm as shown in figure. Find the force 'F' required to lift the weight 'W' = 30 KN.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The ratio of force applied in ram to the area of ram is equal to ratio of force applied in plunger to the area of plunger, as the pressure intensity is same.
\(\frac{F_{ram}}{A_{ram}}=\frac{F_{plunger}}{A_{plunger}}\)
Calculation:
Given: \(A_{ram}=30\times30cm\), \(F_{ram}=30kN\), \(A_{plunger}=4\times4cm\), Fplunger=?.
\(F_{plunger}=30\times\frac{4\times4}{30\times30}=0.53333kN=533.33N\)
Last updated on May 28, 2025
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