Question
Download Solution PDFTwo equal circles of radius 8 cm intersect each other in such a way that each passes through the centre of the other. The length of the common chord is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
The radius of the circles is 8 cm
Calculation:
According to the diagram,
AD = DB
O1O2 = 8
Again O1A = O2A = 8 [Radius of the circle]
∠ADO1 = 90°
O1D = O2D = 4
AD = √(64 - 16)
⇒ √48 = 4√3
AB = 2 × 4√3 = 8√3
∴ The length of the common chord is 8√3 cm
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