Two capacitors of 15μF and 30μF are connected in series. The circuit current when this combination is connected across 50 Hz, 200V supply mains is ________.

Concept:

If two capacitors (C₁,C₂) are in series then their equivalent capacitance(Ceq)

1/Ce_q =1/C₁ + 1/C₂

Reactance offered by a capacitor is given by;

X_C = 1/ωC = 1/2πfC Ω 

Current through the capacitor

I_C = V/X_C

Calculation:

Given;

C1 = 15 μf

C₂ = 30 μf

f = 50 Hz

V= 200 V

Then;

C_eq = (15× 30)/(15+30) = 10 μf

XC = 1/ωC = 1/2πfC = 1/(100π × 10 × 10^-6) = 1000/π Ω 

Therefore;

IC = V/XC = 200/(1000/π ) = (π/5) A