Total number of six-digit numbers in which only and all the five digits 1, 3, 5, 7 and 9 appear, is

  1. 56
  2. (12)(6!)
  3. 6!
  4. (52)(6!)

Answer (Detailed Solution Below)

Option 4 : (52)(6!)

Detailed Solution

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Explanation -

Selecting all 5 digits = 5C5 = 1 way

Now, we need to select one more digit to make it a 6 digit number = 5C1 = 5 ways

Total number of permutations = 6!2!

Total numbers = 5C× 5C× (6!/2!)

= (5/2) 6!

Hence Option (4) is correct.

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