The value of (sin32° cos58° + cos32° sin 58°) is:

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RRB Group D 14 Sept 2022 Shift 3 Official Paper
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  1. 3
  2. 2
  3. 1
  4. 0

Answer (Detailed Solution Below)

Option 3 : 1
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Detailed Solution

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Given:

(sin32° cos58° + cos32° sin 58°)

Concept used:

\(sin(90^\circ-\theta)=cos\theta\)

\(cos(90^\circ-\theta)=sin\theta\)

\(sin^2\theta+cos^2\theta=1\)

Calculation:

sin32° cos58° + cos32° sin 58°

= sin32º sin(90°- 58°)+ cos32° cos(90°- 58°)

= sin32° sin32° + cos32° cos32°

= sin232° + cos232°

=1

The correct answer is 1.

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