The highest number of atoms is present in

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Rajasthan 3rd Grade (Maths & Science) Official Paper (Held On: 25 Feb 2023 Shift 2)
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  1. 0.40g Ca
  2. 12 g He
  3. 4 g He
  4. 46 g Na

Answer (Detailed Solution Below)

Option 2 : 12 g He
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Detailed Solution

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CONCEPT:

Number of Atoms and Moles

  • The number of atoms in a given sample can be calculated using the concept of moles and Avogadro's number (6.022 × 1023 atoms per mole).
  • Moles of a substance can be calculated using the formula:

    Moles = Mass of the substance (in grams) / Molar mass (in g/mol)

  • The total number of atoms is then given by:

    Number of Atoms = Moles × Avogadro's number

EXPLANATION

1) 0.40 g Ca:

  • Molar mass of Ca = 40 g/mol
  • Moles of Ca = 0.40 g / 40 g/mol = 0.01 mol
  • Number of Atoms = 0.01 mol × 6.022 × 1023 = 6.022 × 1021

2) 12 g He:

  • Molar mass of He = 4 g/mol
  • Moles of He = 12 g / 4 g/mol = 3 mol
  • Number of Atoms = 3 mol × 6.022 × 1023 = 1.8066 × 1024

3) 4 g He:

  • Molar mass of He = 4 g/mol
  • Moles of He = 4 g / 4 g/mol = 1 mol
  • Number of Atoms = 1 mol × 6.022 × 1023 = 6.022 × 1023

4) 46 g Na:

  • Molar mass of Na = 23 g/mol
  • Moles of Na = 46 g / 23 g/mol = 2 mol
  • Number of Atoms = 2 mol × 6.022 × 1023 = 1.2044 × 1024

Comparing the number of atoms: The highest number of atoms is in 12 g He.

Therefore, the answer is 12 g He.

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