The decay constant of a radioactive substance is λ. The half life and mean life of substance are respectively given by

  1. \(\frac{1}{\lambda }and \frac{log_e2}{\lambda }\)
  2. \(\frac{log_e2}{\lambda }and \frac{1}{\lambda }\)
  3. \(\frac{\lambda}{log_e2}and \frac{1}{\lambda }\)
  4. \(\frac{\lambda}{log_e2}and 2\lambda\)

Answer (Detailed Solution Below)

Option 2 : \(\frac{log_e2}{\lambda }and \frac{1}{\lambda }\)
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Detailed Solution

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CONCEPT:

  • The half-life of a radioactive element (T1/2): The time interval in which the mass of a radioactive substance or the number of atoms reduced to half of its initial value.
  • The expression for the half-life is

\({T_{\frac{1}{2}}} =\frac{ln2}{\lambda}= \frac{{0.693}}{\lambda }\)
Where λ = is the decay rate constant

  • Mean life: The average lifetime of all the nuclei of a particular unstable atomic species is called mean life.

\(τ=\frac{1}{λ}\)

where τ is mean life, and λ is radioactive decay constant

EXPLANATION:

  • The correct relation between the half-life (T) of a radionuclide with its mean life (τ) is expressed as 

⇒ T1/2 = τ ln2

\(\Rightarrow T_{1/2}=\frac{log_e2}{\lambda}\)               \([\because\, \, τ=\frac{1}{λ}]\)

  • Therefore option 2 is correct.
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