Question
Download Solution PDFA radioactive nucleus emits 3 alpha particles and 2 positrons. For the resultant nucleus, the ratio of neutrons to protons is (consider the initial nucleus to have atomic number Z and atomic mass A):
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
For every alpha particle emission mass number decreases by four and number of protons decreases by two and for every positron emission proton number decreases by one.
Number of neutrons=Mass number(A)-number of protons
Explanation:
Initial proton number=Z
Mass number=A
Initial neutron number=A-Z
- \(X^A_{Z}\longrightarrow^{3\alpha}\longrightarrow X^{A-12}_{Z-6}\longrightarrow ^{2\nu}\longrightarrow X^{A-12}_{Z-8}\)
Now, number of protons=Z- 8
Number of neutrons=A-12-(Z-8)=A-Z-4
Ratio of neutrons to protons=\(\frac{A-Z-4}{z-8}\)
Hence the correct answer is Option-1-\(\frac{A-Z-4}{z-8}\).
Last updated on May 26, 2025
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