Question
Download Solution PDFఒక రాంబస్ యొక్క ఒక భుజం యొక్క పొడవు మరియు రెండు కర్ణాలలో ఒకటి 6 సెం.మీ. రాంబస్ యొక్క వైశాల్యం కనుగొనండి. (సెం.మీ 2 లో)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFరాంబస్ యొక్క వికర్ణాలు లంబంగా ఉంటాయి.
ABCD ఒక రాంబస్ అనుకోనుము మరియు AC = 6 సెం.మీ., దీని మధ్య బిందువు O మరియు భుజం AB = 6 సెం.మీ.
కాబట్టి, ΔAOB లో,
⇒ AO2 + OB2 = AB2
⇒ (6/2)2 + OB2 = 62
⇒ 9 + OB2 = 36
⇒ OB2 = 27
⇒ OB = 3√3 సెం.మీ
⇒ BD = 2 × OB = 6√3 సెం.మీ
⇒ రాంబస్ యొక్క వైశాల్యం = (1/2) × (రాంబస్ యొక్క కర్ణాల లబ్దం)
⇒ (1/2) × (6 × 6√3) = 18√3 సెం.మీ2Last updated on Jun 2, 2025
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