Question
Download Solution PDFABC త్రిభుజంలో, AB = 12 సెం.మీ మరియు AC = 10 సెం.మీ, మరియు ∠BAC = 60°. BC భుజం పొడవు యొక్క విలువ ఎంత?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFఇచ్చిన దత్తాంశం:
త్రిభుజంలో, ABC, AB = 12 సెం.మీ మరియు AC = 10 సెం.మీ మరియు ∠BAC = 60°.
ఉపయోగించిన కాన్సెప్ట్:
కొసైన్ నియమం ప్రకారం, a, b మరియు c త్రిభుజం యొక్క మూడు భుజాలు ఉంటే ΔABC మరియు ∠C అనేది AC మరియు AB మధ్య కోణం అయితే, a2 = b2 + c2 - 2bc × cos∠A
సాధన:
కాన్సెప్ట్ ప్రకారం,
BC2 = AB2 + AC2 - 2 × AB × AC × cos60°
⇒ BC2 = 122 + 102 - 2 × 12 × 10 × 1/2
⇒ BC2 = 124
⇒ BC ≈ 11.13
∴ BC యొక్క కొలత 11.13 సెం.మీ.
Last updated on Jun 11, 2025
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