Question
Download Solution PDFAD||BCగా కలిగిన ABCD ఒక సమద్విబాహు సమలంబ/విషమ చతుర్భుజం, AB = 5 సెం.మీ., AD = 8 సెం.మీ. మరియు BC = 14 సెం.మీ. ఆ సమలంబ/విషమ చతుర్భుజం యొక్క వైశాల్యం (సెం.మీ.2 లలో) ఎంత?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFపై పటం నుండి, త్రిభుజం AOBలో పైథాగరస్ సిద్ధాంతం ఉపయోగించి,
⇒ AB2 = BO2 + OA2
⇒ 52 = 32 + OA2
⇒ OA = 4 సెం.మీ. ఇది సమలంబ/విషమ చతుర్భుజం యొక్క ఎత్తుకు సమానం
⇒ వైశాల్యం = 1/2 × (ఎత్తు) × (సమాంతర భుజాల పొడవుల మొత్తం)
⇒ వైశాల్యం = 1/2 × 4 × (8 + 14) = 44
∴ వైశాల్యం 44 సెం.మీ.2
Last updated on Jun 13, 2025
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