Question
Download Solution PDF42 సెం.మీ వ్యాసార్థం యొక్క గోళం కరిగించి 21 సెం.మీ వ్యాసార్థం యొక్క తీగ లాగా మార్చితే, వైర్ యొక్క పొడవును కనుగొనండి.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFఇచ్చినవి :
గోళం యొక్క వ్యాసార్థం = 42 సెం.మీ.
వైర్ యొక్క వ్యాసార్థం = 21 సెం.మీ.
ఫార్ములా:
స్థూపం యొక్క పరిమాణం = πr2h
గోళం యొక్క పరిమాణం = [4/3]πr3
లెక్కింపు:
వైర్ యొక్క పొడవు x గా ఉండనివ్వండి
ప్రశ్న ప్రకారం
π × 21 × 21 × x = [4/3] × π × 42 × 42 × 42 [పరిమాణం స్థిరంగా ఉంటుంది]
⇒ x = (4 × 42 × 42 × 42)/(21 × 21 × 3)
⇒ x = 224 సెం.మీ
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