Question
Download Solution PDFSimplify the given expression,
\(\frac{432\times 432+247\times 247-432\times 247}{432\times 432\times 432+247\times 247\times 247}\)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFFormula Used :
a3 + b3 = (a + b)(a2 + b2 - ab)
Calculation :
⇒ \(\frac{432× 432+247× 247-432× 247}{432× 432× 432+247× 247× 247}\)
⇒ \(\frac{(432)^2 + (247)^2 - 432 × 247}{(432)^3 + (247)^3}\)
⇒ \(\frac{[(432)^2 + (247)^2 - 432 × 247]}{[(432) + (247)](432^2 + 247^2 - 432 \times 247)}\)
⇒ \(\frac{1}{432 + 247}\)
⇒ \(\frac{1}{679}\)
∴ The correct answer is 1/679.
Last updated on Jun 13, 2025
-> The SSC CGL Notification 2025 has been released on 9th June 2025 on the official website at ssc.gov.in.
-> The SSC CGL exam registration process is now open and will continue till 4th July 2025, so candidates must fill out the SSC CGL Application Form 2025 before the deadline.
-> This year, the Staff Selection Commission (SSC) has announced approximately 14,582 vacancies for various Group B and C posts across government departments.
-> The SSC CGL Tier 1 exam is scheduled to take place from 13th to 30th August 2025.
-> Aspirants should visit ssc.gov.in 2025 regularly for updates and ensure timely submission of the CGL exam form.
-> Candidates can refer to the CGL syllabus for a better understanding of the exam structure and pattern.
-> The CGL Eligibility is a bachelor’s degree in any discipline.
-> Candidates selected through the SSC CGL exam will receive an attractive salary. Learn more about the SSC CGL Salary Structure.
-> Attempt SSC CGL Free English Mock Test and SSC CGL Current Affairs Mock Test.
-> Candidates should also use the SSC CGL previous year papers for a good revision.