Refer to the following number series and answer the question that follows (all numbers are single digit numbers only). Counting to be done from left to right only.

(Left) 3 2 4 9 1 8 7 6 3 2 1 5 6 4 7 8 3 9 4 6 5 7 4 1 5 7 2 (Right)

How many such even digits are there each of which is immediately preceded by a perfect square and immediately followed by an odd digit?

(NOTE: 1 is also a perfect square.)

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  1. Three
  2. Two
  3. One
  4. More than three 

Answer (Detailed Solution Below)

Option 2 : Two
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Detailed Solution

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Given series:

3 2 4 9 1 8 7 6 3 2 1 5 6 4 7 8 3 9 4 6 5 7 4 1 5 7 2

Condition to be checked:

Even digit, immediately preceded by a perfect square, and immediately followed by an odd digit.

Perfect Square → Even Digit → Odd Digit

Let's analyze the series for this pattern:

3 2 4 9 1 8 7 6 3 2 1 5 6 4 7 8 3 9 4 6 5 7 4 1 5 7 2

Thus, two such even digits are immediately preceded by a perfect square and immediately followed by an odd digit.

Hence, the correct answer is "Option 2".

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