ज्याचे सरासरी मूल्य 12.74 व्होल्ट आहे अशा साइन तरंगरूपचे सर्वोच्च मूल्य किती आहे?

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ALP CBT 2 Electronic Mechanic Previous Paper: Held on 21 Jan 2019 Shift 2
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  1. 40 V
  2. 30 V
  3. 20 V
  4. 10 V

Answer (Detailed Solution Below)

Option 1 : 40 V
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संकल्पना:

एका पूर्ण चक्रात ज्यावक्रीय तरंगाचे सरासरी मूल्य शून्य असते कारण दोन भाग एकमेकांना रद्द करतात, त्यामुळे सरासरी मूल्य अर्ध्या चक्रावर घेतले जाते.

 

\({V_{avg}} = \frac{1}{\pi }\mathop \smallint \nolimits_0^\pi {V_p}\sin \theta \;d\theta \)

\({V_{avg}} = \frac{{{V_p}}}{\pi }\left( { - \cos \theta } \right)_0^\pi \)

\({V_{avg}} = \frac{{2{V_p}}}{\pi } = 0.637 × {V_p}\)

म्हणून, ज्यावक्रीय तरंगाचे सरासरी मूल्य शिखर मूल्याच्या 0.637 पट आहे.

F1 U.B. Nita 11.11.2019 D 2

गणना:

दिले आहे,

Vavg = 12.74 V

\({V_{avg}} = \frac{{2{V_p}}}{\pi } = 0.637 × {V_p}\)

\(V_p=\frac{12.47}{0.637}~ V\)

= 19.57 V

∵ आपल्याला सर्वोच्च व्होल्टेज शोधण्यास सांगितले जाते.

∴ Vp-p = 2 × 19.57 ≈ 40 V

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