Question
Download Solution PDFवास्तविक आणि समान मुळे असलेले द्विघात समीकरण \(\frac{3}{5}\) आहे :
Answer (Detailed Solution Below)
Detailed Solution
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चतुर्भुज समीकरणाला वास्तविक आणि समान मुळे असतात
गणना:
मुळे m आणि n असू द्या
प्रश्नानुसार,
मी = \(\frac{3}{5}\) , आणि n = \(\frac{3}{5}\)
आता, मुळांची बेरीज = m + n = \(\frac{3}{5}\) + \(\frac{3}{5}\)
मुळांची बेरीज = \(6\over5\)
मुळांचे उत्पादन = mn = \(\frac{3}{5}\) * \(\frac{3}{5}\)
मुळांचे उत्पादन = \(9\over25\)
आता, चतुर्भुज समीकरण सूत्रामध्ये मूल्ये ठेवा,
x 2 - (m + n)x + mn = 0
x 2 - \(6\over5\) x + \(9\over25\) = 0
सोडवताना आम्हाला मिळते,
25x 2 - 30x + 9 = 0
25x 2 - 30x + 9 = 0
म्हणून, द्विघात समीकरण '25x 2 - 30x + 9 = 0' असेल.
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