Question
Download Solution PDFसंख्यांचा विसंगत गट निवडा. (टीप: संख्यांचे घटक अंकांमध्ये विभाजन न करता संपूर्ण संख्यांवर क्रिया केल्या पाहिजेत. उदा.13 – 13 वरील क्रिया जसे की 13 ची बेरीज/वजाबाकी/गुणाकार करणे इ. 13 चे 1 आणि 3 मध्ये विभाजन करणे आणि नंतर 1 आणि 3 वर गणिती क्रिया करण्यास अनुमती नाही)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFतर्क:
- पहिली संख्या = दुसऱ्या संख्येचे घनमूळ
- दुसरी संख्या - तिसरी संख्या = 10
म्हणून,
- पर्याय - (1) : (7 – 343 – 331)
7 = 3√343
7 = 7 (डावी बाजू = उजवी बाजू)
आणि,
343 - 331 = 12
- पर्याय - (2) : (6 – 216 – 206)
6 = 3√216
6 = 6 (डावी बाजू = उजवी बाजू)
आणि,
216 - 206 = 10
- पर्याय - (3) : (5 – 125 – 115)
5 = 3√125
5 = 5 (डावी बाजू = उजवी बाजू)
आणि,
125 - 115 = 10
- पर्याय - (4) : (3 – 27 – 17)
3 = 3√27
3 = 3 (डावी बाजू = उजवी बाजू)
आणि,
27 - 17 = 10
येथे, केवळ पर्याय - (1) मध्ये दुसरी संख्या आणि तिसऱ्या संख्येमधील फरक 10 ऐवजी 12 आहे. अशा प्रकारे, ती विसंगत आहे.
म्हणून, "पर्याय - (1)" हे योग्य उत्तर आहे.
Last updated on Jun 25, 2025
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