Question
Download Solution PDFചുവടെയുള്ള ചിത്രം പരിഗണിക്കുമ്പോൾ, കോൺ ABO = 30°യും വൃത്തത്തിൻ്റെ ചുറ്റളവ് 44 സെ.മീ. ഉം ആണെങ്കിൽ, സ്പർശരേഖ ABയുടെ നീളം കണ്ടെത്തുക?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFവൃത്തത്തിൻ്റെ ചുറ്റളവ് = 2πr
⇒ 44 = 2 × (22/7) × (r)
⇒ r = AO = 7 സെ.മീ.
ഒരു വൃത്തത്തിൻ്റെ സ്പർശരേഖ, സ്പർശരേഖാ ബിന്ദുവിൽ നിന്ന് വരച്ച, ആരത്തിന് ലംബമായിരിക്കും.
അതിനാൽ, ∆AOB ഒരു മട്ടത്രികോണമാണ്
⇒ tan 30° = OA/AB
⇒ 1/√3 = 7/AB
⇒ AB = 7√3
∴ അതിനാൽ AB = 7√3
Last updated on Jun 9, 2025
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