In first order reaction the conc. of reactant decreases from 1.0 M to 0.25 M in 20 minutes, the value of k is -

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  1. 0.06932
  2. 0.6932
  3. 6.932 
  4. None of these

Answer (Detailed Solution Below)

Option 1 : 0.06932
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HPSC Asst Prof. Commerce Subject Test 1
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Detailed Solution

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CONCEPT:

First Order Reaction Kinetics

  • For a first-order reaction, the rate of reaction is directly proportional to the concentration of the reactant.
  • The integrated rate law for a first-order reaction is given by:
    \( \ln \left(\frac{[R]_0}{[R]}\right) = kt \), where:
    • \([R]_0\) is the initial concentration of the reactant.
    • [R] is the concentration of the reactant at time t.
    • k is the rate constant.
    • t is the time.

CALCULATION:

  • Given data:
    • Initial concentration \([R]_0 = 1.0 \, M\)
    • Final concentration \([R] = 0.25 \, M\)
    • Time \(t = 20 \, minutes\)
  • Using the first-order integrated rate law:
    • \(\ln \left(\frac{[R]_0}{[R]}\right) = kt \)
    • \(\ln \left(\frac{1.0}{0.25}\right) = k \times 20 \, minutes\)
    • \(\ln(4) = k \times 20\)
    • \(k = \frac{\ln(4)}{20} \approx \frac{1.386}{20} \approx 0.06932 \, \text{min}^{-1}\)

The correct answer is (1) 0.06932.

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