In an irrigated field, the crop requires 60 cm of water in 15 days, while the effective rainfall during that period is recorded as 15 cm. Find the duty at the head of field. Assume no losses

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  1. 298 ha/cumec
  2. 268 ha/cumec
  3. 278 ha/cumec
  4. 288 ha/cumec

Answer (Detailed Solution Below)

Option 4 : 288 ha/cumec
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concept:


Using the relation \({\rm{\Delta }} = \frac{{864\;B}}{D}\;\)

Δ → depth of water required (cm)

D → Duty (hectares per cumec)

B → Base period (days)

Effective Δ = 60-15=45 cm, 

B = 15 days

\(D = \frac{{864 \times 15}}{{45}}\)

D = 288 ha/cumec

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