Question
Download Solution PDFIf the initial tension on a stretched string is doubled, then the ratio of the initial and final speeds of a transverse wave along the string is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCONCEPT:
The speed v of the transverse wave is directly proportional to the square root of the tension and it is written as;
\(v \propto \sqrt T\)
Here, v is the speed and T is the tension.
CALCULATION:
As we know that;
\(v \propto \sqrt T\)
The initial tension of the string is written as;
\(v_1 \propto \sqrt T\) -----(1)
When the string is stretched, the initial tension is doubled.
\(v_2 \propto \sqrt {2T}\) -----(2)
Now, on dividing equation (1) by equation (2) we have;
\(\frac {v_1}{v_2} = \frac{1}{\sqrt2}\)
Hence option 4) is the correct answer.
Last updated on Jun 14, 2025
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