Question
Download Solution PDFIf tan x = \(−\frac{12}{5}\), where x lies in the second quadrant, what is the value of sin x − cot x?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven
tan x = -12/5
Concept
tan x = Perpendicular/base
Sin x = Perpendicular/hypotenuse
Calculation
tan x = -12/5 = Perpendicular/base
P = 12 and B = - 5
H2 = P2 + B2
H2 = 144 + 25
H2 = 169
H = 13
⇒ sin x − cot x
⇒ P/H + B/P ...(since cot is also negative in second quadrant)
⇒ (P2 + BH)PH
⇒ (144 + 65)/156
⇒ 209/156
The value is 209/156.
Last updated on Jun 13, 2025
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