If \(\rm\sqrt{\left(1−\frac{99}{2500}\right)}=\frac{49}{\sqrt{x}} \), then the value of x is:

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Question

This question was previously asked in

RRB Group D 9 Sept 2022 Shift 2 Official Paper

Answer 1

Given:

\(\rm\sqrt{\left(1−\frac{99}{2500}\right)}=\frac{49}{\sqrt{x}}\)

Calculation:

Here, we have \(\rm\sqrt{\left(1−\frac{99}{2500}\right)}=\frac{49}{\sqrt{x}}\)

On squaring both sides, we get

⇒ \({\left(1−\frac{99}{2500}\right)}=\frac{2401}{{x}}\)

⇒ \(\frac{(2500−99)}{2500}=\frac{2401}{{x}}\)

⇒ \(\frac{2401}{2500}=\frac{2401}{{x}}\)

⇒ x = 2500

Hence, the required value is 2500.

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