Question
Download Solution PDFIf b = 5, determine the value of an expression \(({5 \over b} + 5b)\) \(({25 \over b^2} - 25 + 25b^2)\) using an identity.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFb = 5
Formula used:-
A3 + B3 =(A + B) (A2 + B2 - AB)
Calculation:-
(5/b + 5b)(25/b2 - 25 +25b2)
⇒ (5/b)3 + (5b)3
Put the value of "b" in the above equation
⇒ (5/5)3 + (5 × 5)3
⇒ 1 + (25)3
⇒ 1 + 15625 = 15626
∴ The required answer is 15626.
Last updated on Jun 13, 2025
-> The SSC CGL Notification 2025 has been released on 9th June 2025 on the official website at ssc.gov.in.
-> The SSC CGL exam registration process is now open and will continue till 4th July 2025, so candidates must fill out the SSC CGL Application Form 2025 before the deadline.
-> This year, the Staff Selection Commission (SSC) has announced approximately 14,582 vacancies for various Group B and C posts across government departments.
-> The SSC CGL Tier 1 exam is scheduled to take place from 13th to 30th August 2025.
-> Aspirants should visit ssc.gov.in 2025 regularly for updates and ensure timely submission of the CGL exam form.
-> Candidates can refer to the CGL syllabus for a better understanding of the exam structure and pattern.
-> The CGL Eligibility is a bachelor’s degree in any discipline.
-> Candidates selected through the SSC CGL exam will receive an attractive salary. Learn more about the SSC CGL Salary Structure.
-> Attempt SSC CGL Free English Mock Test and SSC CGL Current Affairs Mock Test.
-> Candidates should also use the SSC CGL previous year papers for a good revision.