Question
Download Solution PDFIf an object is placed in front of a concave mirror at a distance of 20 cm and the image is formed on the same side at a distance of 40 cm, then the magnification of the mirror will be:
This question was previously asked in
RRB Technician Grade III Official Paper (Held On: 29 Dec, 2024 Shift 1)
Answer (Detailed Solution Below)
Option 4 : -2.0
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Download Solution PDFThe correct answer is -2.
Key Points
- The magnification (m) of a mirror is calculated using the formula: m = -v/u, where 'v' is the image distance and 'u' is the object distance.
- Here, the object distance (u) is -20 cm (negative as it is in front of the mirror) and the image distance (v) is -40 cm (negative as it is a real image formed on the same side as the object).
- Substituting the values, m = -(-40 cm) / (-20 cm) = 40 / 20 = 2.0.
- Since the image is real and inverted, the magnification will be negative: m = -2.0.
- Thus, the correct magnification of the mirror is -2.0, which corresponds to option 4.
Additional Information
- Concave Mirrors:
- Concave mirrors are spherical mirrors that curve inward, resembling a portion of the interior of a sphere.
- They are known to converge light rays to a focal point, making them useful in applications like telescopes and shaving mirrors.
- Mirror Formula:
- The mirror formula relates object distance (u), image distance (v), and focal length (f) through the equation: 1/f = 1/u + 1/v.
- Magnification:
- Magnification (m) indicates how much larger or smaller the image is compared to the object.
- For mirrors, it is calculated as the ratio of the image height to the object height or -v/u for distances.
- Real vs. Virtual Images:
- Real images are formed when light rays converge and can be projected on a screen; they are inverted.
- Virtual images occur when light rays only appear to diverge from a point; they are upright.
Last updated on Jun 30, 2025
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