Question
Download Solution PDF\( \begin{bmatrix} 0 & 4 & 6\\ -4 & 0&-2 \\ -6& 2 & 0 \end{bmatrix}\) के M23 का उपसारणिक क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFअवधारणा:
माना, A = [aij] एक वर्ग आव्यूह है।
उपसारणिक Mij, और सह-खंड Cij, की गणना करने के लिए, हम दिए गए आव्यूह के सारणिक को पंक्ति i और स्तंभ j को हटाते हैं।
तो, Cij = (-1)i+j Mij , जहां, Mij = आव्यूह A का उपसारणिक
गणना:
दिया हुआ है कि:
\( \begin{bmatrix} 0 & 4 & 6\\ -4 & 0&-2 \\ -6& 2 & 0 \end{bmatrix}\)
दूसरी पंक्ति और तीसरे स्तंभ को हटाकर हम सारणिक को इस रूप में प्राप्त करते हैं
\(\begin{vmatrix} 0 & 4\\ -6 & 2\end{vmatrix}\)
= 0 × 2 - (-6) × 4
= 24
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