Question
Download Solution PDFThe starting current of a three-phase induction motor is equal to three times the full-load current. If the full-load slip is 2%, then the starting torque as a percentage of full-load torque is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
प्रारंभिक बलाघूर्ण और पूर्ण भार बलाघूर्ण के बीच अनुपात को निम्न द्वारा ज्ञात किया गया है:
\(\frac{{{T}_{st}}}{{{T}_{fl}}}={{s}_{fl}}\times {{\left( \frac{{{I}_{st}}}{{{I}_{fl}}} \right)}^{2}}\)
जहाँ Tst प्रारंभिक बलाघूर्ण है।
Tfl पूर्ण भार बलाघूर्ण है।
sfl पूर्ण भार पर सर्पी है।
Ist प्रारंभिक धारा है।
Ifl रेटेड धारा है।
गणना:
3-ϕ वाले प्रेरण मोटर की प्रारंभिक धारा रेटेड धारा का 3 गुना होती है अर्थात्
Ist = 3 Ifl
पूर्ण भार सर्पी (sfl) = 2 %
\(\frac{{{T}_{st}}}{{{T}_{fl}}}={0.02}\times {{\left( \frac{{3}}{{1}} \right)}^{2}}\)
= 18 %
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