Question
Download Solution PDFप्रति सेकेंड 200 जूल ऊष्मा उत्पन्न होने पर, 2 ओह्म के एक प्रतिरोध के टर्मिनलों के बीच विभवांतर ______होगा।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया:
उत्पादित ऊष्मा = 200 जूल
प्रतिरोध=2 ओम
प्रयुक्त सूत्र:
उत्पादित ऊष्मा की मात्रा \(H=\frac{V^2t}{R}\)
[जहाँ V उत्पादित वोल्टेज की मात्रा है; t आवश्यक समय है; R प्रतिरोध है]
गणना:
\(200=\frac{\mathrm{V}^2 \times 1}{2}\\ \Rightarrow \mathrm{V}^2=400 \\\Rightarrow \mathrm{V}=20 \mathrm{v}\)
अतः सही उत्तर 20 वोल्ट है।
Last updated on Jul 11, 2025
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