Question
Download Solution PDFसमीकरण cos (2 sin-1 x) = 1/9 के लिए x का मान ज्ञात कीजिए जहाँ x > 0।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFधारणा:
cos 2x = 1 - 2 sin2 x
गणना:
दिया हुआ: cos (2 sin-1 x) = 1/9 जहाँ x > 0
माना कि sin-1 x = y
⇒ x = sin y
⇒ cos (2 sin-1 x) = cos 2y = 1/9
जैसा कि हम जानते हैं कि, cos 2x = 1 - 2 sin2 x
⇒ 1 - 2 sin2 y = 1/9
⇒ 2sin2 y = 8/9
⇒ x2 = 4/9 --------(∵ x = sin y)
⇒ x = ± 2/3
लेकिन जैसा कि यह दिया गया है कि x > 0
⇒ x = 2/3
Last updated on May 30, 2025
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