निम्नलिखित परिपथ में टर्मिनल AB पर तुल्यांकी प्रेरकत्व का मान ज्ञात कीजिए।

F2 ENG Savita 17-1-24 D1

This question was previously asked in
SSC JE Electrical 10 Oct 2023 Shift 2 Official Paper-I
View all SSC JE EE Papers >
  1. 36 H
  2. 26 H
  3. 23 H
  4. 50 H

Answer (Detailed Solution Below)

Option 3 : 23 H
Free
Electrical Machine for All AE/JE EE Exams Mock Test
7.7 K Users
20 Questions 20 Marks 20 Mins

Detailed Solution

Download Solution PDF

अवधारणा

जब दो प्रेरक श्रेणीक्रम में जुड़े होते हैं, तो तुल्यांकी प्रेरकत्व इस प्रकार दिया जाता है:

\(L_{eq}=L_1+L_2\)

जब दो प्रेरक समानांतर क्रम में जुड़े होते हैं, तो तुल्यांकी प्रेरकत्व इस प्रकार दिया जाता है:

\(L_{eq}={L_1L_2\over L_1+L_2}\)

गणना:

3H और 1H श्रेणीक्रम में जुड़े हुए हैं।

L = 3 + 1 = 4H

4H और 12H समानांतर क्रम में जुड़े हुए हैं।

\(L={4\times 12\over 4+12}=3H\)

5H, 3H और 15H श्रेणीक्रम में जुड़े हुए हैं।

Lतुल्यांकी = 23 H

Latest SSC JE EE Updates

Last updated on Jul 1, 2025

-> SSC JE Electrical 2025 Notification is released on June 30 for the post of Junior Engineer Electrical, Civil & Mechanical.

-> There are a total 1340 No of vacancies have been announced. Categtory wise vacancy distribution will be announced later.

-> Applicants can fill out the SSC JE application form 2025 for Electrical Engineering from June 30 to July 21.

-> SSC JE EE 2025 paper 1 exam will be conducted from October 27 to 31. 

-> Candidates with a degree/diploma in engineering are eligible for this post.

-> The selection process includes Paper I and Paper II online exams, followed by document verification.

-> Prepare for the exam using SSC JE EE Previous Year Papers.

More Network Elements Questions

Get Free Access Now
Hot Links: teen patti wala game all teen patti master teen patti master new version teen patti master purana