(0.72 × 0.26 + 0.18 × 0.52) ÷ (0.13 × 0.9) का मान ज्ञात कीजिये। 

  1. 3.4
  2. 0.024
  3. 2.4
  4. 0.034

Answer (Detailed Solution Below)

Option 3 : 2.4
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SSC MTS 2024 Official Paper (Held On: 01 Oct, 2024 Shift 1)
90 Qs. 150 Marks 90 Mins

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दिया गया है:

(0.72 × 0.26 + 0.18 × 0.52) ÷ (0.13 × 0.9)

प्रयुक्त सिद्धांत

नीचे दिए गए तालिका के अनुसार BODMAS नियम का अनुसरण कीजिये

गणना:

(0.72 × 0.26 + 0.18 × 0.52) ÷ (0.13 × 0.9)

⇒ (0.1872 + 0.0936) ÷ 0..117

⇒ 0.2808 ÷ 0.117 = 2.4

या हम व्यंजक के मान की गणना इस तरह से कर सकते हैं

(0.72 × 0.26)/(0.13 × 0.9) + (0.18 × 0.52)/(0.13 × 0.9)

⇒ 1.6 + 0.8 = 2.4

∴ 2.4

Latest SSC MTS Updates

Last updated on Jul 14, 2025

-> The IB ACIO Notification 2025 has been released on the official website at mha.gov.in.

-> SSC MTS Notification 2025 has been released by the Staff Selection Commission (SSC) on the official website on 26th June, 2025.

-> For SSC MTS Vacancy 2025, a total of 1075 Vacancies have been announced for the post of Havaldar in CBIC and CBN.

-> As per the SSC MTS Notification 2025, the last date to apply online is 24th July 2025 as per the SSC Exam Calendar 2025-26.

-> The selection of the candidates for the post of SSC MTS is based on Computer Based Examination. 

-> Candidates with basic eligibility criteria of the 10th class were eligible to appear for the examination. 

-> Candidates must attempt the SSC MTS Mock tests and SSC MTS Previous year papers for preparation.

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