Find the value of the expression given below, correct upto 2 decimal places.

$\frac{(0.96)^{3} - (0.1)^{3}}{(0.96)^{2} + 0.096 + (0.1)^{2}}$

Question

Question

Answer 1

Given:

The value of $\frac{{(0.96)}^{3} - {(0.1)}^{3}}{{(0.96)}^{2} + 0.096 + {(0.1)}^{2}}$

Formula Used:

$\frac{a^{3} - b^{3}}{a^{2} + a b + b^{2}} = a - b$

Calculation:

Here, a = 0.96 and b = 0.1 .

Using the formula:

$\frac{(0.96)^{3} - (0.1)^{3}}{(0.96)^{2} + (0.96 \times 0.1) + (0.1)^{2}}$

⇒ $\frac{(0.96)^{3} - (0.1)^{3}}{(0.96)^{2} + 0.096 + (0.1)^{2}}$

⇒ 0.96 - 0.1

⇒ 0.86

The correct answer is option 3.

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