During the measurement of voltage, the voltmeter responded with a 0.18-V change when the input was varied by 0.2 V. Find the sensitivity of the instrument.

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SSC JE EE Previous Paper 12 (Held on: 24 March 2021 Evening)
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  1. 0.9
  2. 0.18
  3. 0.1
  4. 0.2

Answer (Detailed Solution Below)

Option 1 : 0.9
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Detailed Solution

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concept:

Sensitivity(S) of instrument is defined as change in output with respect to change in input

S = \(\frac{dV_0}{dV_i}=\frac{Δ V_0}{Δ V_i}\)

Where

V0 = Output voltage of instrument

Vi = Input voltage of instrument

Application:

Given:

ΔV0 = 0.18 V

ΔVi =0.2 V

S = \(\frac{0.18}{0.2}\) = 0.9

Important Points

  •  For any Instrument, Even for a small change in input there should be a large change in output i.e sensitivity should be higher
  •  For any disturbances in the system the output should not be affected much i.e sensitivity should be lower.
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