Question
Download Solution PDFDue to an acceleration of 4 m/s2 the velocity of a body increases from 10 m/s to 30 m/s in a certain period. Find the displacement (in m) of the body in that period.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCONCEPT:
- Equation of motion: The mathematical equations used to find the final velocity, displacements, time, etc of a moving object without considering force acting on it are called equations of motion.
- These equations are only valid when the acceleration of the body is constant and they move on a straight line.
- There are three equations of motion:
V = u + at
V2 = u2 + 2 a S
\({\text{S}} = {\text{ut}} + \frac{1}{2}{\text{a}}{{\text{t}}^2}\)
Where, V = final velocity, u = initial velocity, s = distance traveled by the body under motion, a = acceleration of body under motion, and t = time taken by the body under motion.
EXPLANATION:
v = 30 m/s, u = 10 m/s, a = 4 m/s2
We know that,
⇒ v2 = u2 + 2aS
⇒ 2aS = v2 – u2
⇒ 2 × 4 × S = 900 - 100
⇒ 8S = 800
Last updated on May 28, 2025
-> The SSC has released the SSC CHSL exam calendar for various exams including CHSL 2025 Recruitment. As per the calendar, SSC CHSL Application process will be active from 23rd June 2025 to 18th July 2025.
-> The Exam Date for the SSC CHSL 2025 will be from 8th September 2025 to 18th September, 2025.
-> The SSC CHSL is conducted to recruit candidates for various posts such as Postal Assistant, Lower Divisional Clerks, Court Clerk, Sorting Assistants, Data Entry Operators, etc. under the Central Government.
-> The SSC CHSL Selection Process consists of a Computer Based Exam (Tier I & Tier II).
-> To enhance your preparation for the exam, practice important questions from SSC CHSL Previous Year Papers. Also, attempt SSC CHSL Mock Test.