Due to an acceleration of 4 m/s2 the velocity of a body increases from 10 m/s to 30 m/s in a certain period. Find the displacement (in m) of the body in that period.

This question was previously asked in
SSC CHSL Previous Paper 49 (Held On: 10 March 2018 Shift 3)
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  1. 200
  2. 250
  3. 100
  4. 125

Answer (Detailed Solution Below)

Option 3 : 100
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SSC CHSL Exam 2023 Tier-I Official Paper (Held On: 02 Aug 2023 Shift 1)
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Detailed Solution

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CONCEPT:

  • Equation of motion: The mathematical equations used to find the final velocity, displacements, time, etc of a moving object without considering force acting on it are called equations of motion.
  • These equations are only valid when the acceleration of the body is constant and they move on a straight line.
  • There are three equations of motion:

V = u + at

V2 = u2 + 2 a S

\({\text{S}} = {\text{ut}} + \frac{1}{2}{\text{a}}{{\text{t}}^2}\)

Where, V = final velocity, u = initial velocity, s = distance traveled by the body under motion, a = acceleration of body under motion, and t = time taken by the body under motion.

EXPLANATION:

v = 30 m/s, u = 10 m/s, a = 4 m/s2

We know that,

⇒ v2 = u2 + 2aS

⇒ 2aS = v2 – u2

⇒ 2 × 4 × S = 900 - 100

⇒ 8S = 800

⇒ S = 800/8 = 100m
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