Question
Download Solution PDFConsider the circuit as shown in the figure below:
The Q-factor of the inductor is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The quality factor is given by:
\(Q ={1\over R} {\sqrt{L\over C }}\)
where Q = Quality factor
R = Resistance
L = Inductor
C = Capacitance
Calculation:
Given R= 5Ω, L= 1H, C= 2mF
\(Q ={1\over 5} {\sqrt{1\over 2\times 10^{-3} }}\)
\(Q = {\sqrt{1000\over 2\times 25 }}\)
\(Q ={\sqrt{20 }}\)
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