Consider diffraction of light from a single slit. Ratio of the intensity of central maximum to that of the first maximum lying on either side of the central maximum is

Concept:

Diffraction is the phenomenon when passes through space or hole it tends to spread out, this phenomenon of waves is known as diffraction.

• The diffraction from the slit of the first maximum to the central maximum is the function of sinusoidal waves which can be expressed as 

The intensity is given by :

\(I=I_0 (\frac{sin(\phi/2)}{\phi/2})\)

For nth second maxima, dsinθ = (2n+1)/2\(\lambda\)

So, \(\frac{\phi}{2} = \frac{\pi}{2}[d sin\theta] = \frac{2n+1}{2}\lambda\)

So, \(I=I_o(\frac{sin(2n+1)\lambda/2}{(2n+1)\lambda/2})^2\)

\(I=\frac{I_o}{{(2n+1)\lambda/2})^2}\)

So \(I_0:I_1 = I_o: \frac{4I_o}{9\pi^2}\)

\(I_0:I_1 =1:0.045\)

\(I_0:I_1 =1000:45 = 200:9\)

Note: This question was deleted in RSMSSB Lab Assistant 2016 Exam