Question
Download Solution PDF45 কিমি/ঘন্টা গড় গতিবেগে একটি ট্রেন সময়মতো তার গন্তব্যে পৌঁছায়। যদি এটি গড়ে 30 কিমি/ঘন্টা গতিবেগে যায়, তবে এটি 15 মিনিট দেরি করে। মোট যাত্রাপথ হল:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFপ্রদত্ত:
প্রকৃত গতিবেগ = 45 কিমি/ঘন্টা
হ্রাস গতিবেগ = 30 কিমি/ঘন্টা
অনুসৃত সূত্র :
মোট দূরত্ব = \(\frac{(S_1 × S_2)}{S_1-S_2} \times (T_1+T_2)\)
এখানে,
S 1 = প্রকৃত গতিবেগ
S 2 = হ্রাস গতিবেগ
T 1 = সময় 1
T 2 = সময় 2
গণনা:
ধারণা অনুযায়ী,
মোট দূরত্ব = \(\frac{(45 × 30)}{45-30} \times (0+\frac{1}{4})\)
⇒ \(\frac{(1350)}{15} \times \frac{1}{4}\)
⇒ 22.5 কিমি
∴ A এবং B এর মধ্যে দূরত্ব 22.5 কিমি।
Last updated on Jul 12, 2025
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