Question
Download Solution PDF142!-তে কতগুলি শূন্য রয়েছে?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFপ্রদত্ত:
142!-তে শেষে শূন্যের সংখ্যা
অনুসৃত ধারণা:
n!-এ শেষে শূন্যের সংখ্যা = n!-কে 10 দিয়ে যতোবার বিভাজ্য = 10-এর সর্বাধিক ঘাত যা দ্বারা n! বিভাজ্য = n!-এ 5-এর সর্বোচ্চ ঘাত
গণনা:
প্রশ্নানুসারে,
142/5 = 28
28/5 = 5
5/5 = 1
∴ মোট শূন্যের সংখ্যা = 28 + 5 + 1 = 34Last updated on Jun 7, 2025
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