An electric lamp of 30 Ω resistance and a conductor of 6 Ω resistance are connected in series to a 6 V battery. The total resistance of the circuit is:

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RRB Group D 17 Sept 2022 Shift 3 Official Paper
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  1. 30 Ω
  2. 36 Ω
  3. 24 Ω
  4. 42 Ω

Answer (Detailed Solution Below)

Option 2 : 36 Ω
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Detailed Solution

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The correct answer is 36 Ω.

Key Points

Given:

Electric lamp resistance is 30 Ω and conductor resistance is 6 Ω which are connected in series to  6 V battery.

Formula:

For, resistors in series we have:

 \(Rs=R1+R2+....+Rn\)

Calculations:

\(R1=30 Ω \)

\(R2=6 Ω \)

\(Rs=R1+R2=30+6=36​Ω\)

Therefore, total resistance of the circuit is 36 Ω.

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