ΔABC is inscribed in a circle with centre O. If AB = 17 cm, BC = 10 cm and AC = 9 cm, find the length of AO 

  1. 18 cm
  2. 10.6 cm
  3. 106 cm
  4. 36 cm

Answer (Detailed Solution Below)

Option 2 : 10.6 cm
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PYST 1: SSC CGL - English (Held On : 11 April 2022 Shift 1)
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Detailed Solution

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Concept used:

Length of circumradius = (A × B × C)/(4 × Δ)    

where A, B, C are the lengths of the 3 sides of the triangle

Δ → Area of the triangle.

Area of triangle = √{s(s - a)(s - b)(s - c)}   

where a, b, c are the lengths of the 3 sides of the triangle

s → Semiperimeter

Calculation: 

F1 Harshit 1.2.21 Pallavi D1

s = (a + b + c)/2

⇒ s = (10 + 9 + 17)/2

⇒ s = 18

Area of ΔABC = √{18(18 - 10)(18 - 9)(18 - 17)

⇒ √(18 × 8 × 9 × 1)

⇒ 36 cm2

Circumradius of the triangle = (a × b × c)/4Δ

⇒ (10 × 17 × 9)/(4 × 36)

⇒ 10.6 cm

∴ Circumradius of the triangle is 10.6 cm

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