Question
Download Solution PDFA tap can fill a cistern in 24 minutes and another tap can empty it in 36 minutes. If both the taps are open, the time taken to fill the tank will be:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Tap 1 fills the cistern in 24 minutes.
Tap 2 empties the cistern in 36 minutes.
Formula used:
Net rate of filling = Rate of filling by Tap 1 - Rate of emptying by Tap 2
Time taken = Volume / Net rate of filling
Calculations:
Rate of filling by Tap 1 = 1/24 cistern/min
Rate of emptying by Tap 2 = 1/36 cistern/min
Net rate of filling = 1/24 - 1/36
⇒ Net rate = (3 - 2) / 72 = 1/72 cistern/min
Time taken to fill the cistern = 1 / (1/72) = 72 minutes
∴ The correct answer is option (1).
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