Question
Download Solution PDFA random sample of size 225 is drawn from the population of mean μ and standard deviation σ. The sample mean follows the distribution with mean 100 and standard distribution 4/3. The value of μ and σ are:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe correct answer is (100, 20).
Key Points
- The sample mean is an estimator of the population mean, but the true population mean is usually not known.
- The standard deviation of the sample mean decreases as the sample size increases.
- In general, larger sample sizes lead to more accurate estimates of population parameters.
Additional Information
- The sample mean follows a normal distribution with mean 100 and standard deviation 4/3.
- The sample size is 225.
- The standard deviation of the population, σ, can be calculated using the formula σ = standard deviation of the sample mean * (square root of the sample size), where the standard deviation of the sample mean is 4/3.
- σ = 4/3 * (square root of 225) = 20
- So, the population mean is μ = 100 and the standard deviation is σ = 20.
Last updated on Jul 10, 2025
-> The SSC CGL Application Correction Window Link Live till 11th July. Get the corrections done in your SSC CGL Application Form using the Direct Link.
-> This year, the Staff Selection Commission (SSC) has announced approximately 14,582 vacancies for various Group B and C posts across government departments.
-> The SSC CGL Tier 1 exam is scheduled to take place from 13th to 30th August 2025.
-> Aspirants should visit ssc.gov.in 2025 regularly for updates and ensure timely submission of the CGL exam form.
-> Candidates can refer to the CGL syllabus for a better understanding of the exam structure and pattern.
-> The CGL Eligibility is a bachelor’s degree in any discipline.
-> Candidates selected through the SSC CGL exam will receive an attractive salary. Learn more about the SSC CGL Salary Structure.
-> Attempt SSC CGL Free English Mock Test and SSC CGL Current Affairs Mock Test.